Evaluation of definite integral

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Homework Help Overview

The discussion revolves around evaluating the definite integral of the function x/(x^3+1) over the entire real line, which involves considerations of singularities and convergence.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the challenges of integrating around the singularity at x = -1 and question the appropriate contour to use. There are considerations about the convergence of the integral before applying contour integration techniques.

Discussion Status

Some participants have raised concerns about the convergence of the integral, with references to computational tools like Mathematica and MATLAB suggesting that the integral may not converge. There is no explicit consensus on the evaluation of the integral, but various interpretations and approaches are being explored.

Contextual Notes

Participants are considering the implications of the singularity at x = -1 and the nature of the integral over the entire real line, which may affect the evaluation process.

NT123
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Homework Statement

Need to evaluate int(-inf,inf)(x/(x^3+1)).



Homework Equations





The Attempt at a Solution

I don't believe finding the residues will be a problem. However, the integral is over the whole real line, and there is a singularity at -1 on the real line, so I'm not sure how to draw an appropriate contour to integrate around. Am I supposed to integrate over a keyhole contour avoiding the singularity at -1 from the right and then from the left? Any help / advice will be much appreciated.
 
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You might want to check if the integral actually exists/converges before worrying about contours.
 
gabbagabbahey said:
You might want to check if the integral actually exists/converges before worrying about contours.

My book says it is equal to pi/sqrt(3) :)
 
NT123 said:
My book says it is equal to pi/sqrt(3) :)

Hmm...

[tex]\lim_{\epsilon\to 0} \left[\int_{-\infty}^{-1-\epsilon} \frac{x}{x^3+1}dx+\int^{\infty}_{-1+\epsilon} \frac{x}{x^3+1}dx\right]=\frac{\pi}{\sqrt{3}}[/tex]

But, I don't think you can say that is the same thing as [itex]\int_{-\infty}^{\infty} \frac{x}{x^3+1}dx[/itex]. Mathematica seems to agree with me, that the integral doesn't converge. I don't think [itex]x=-1[/itex] is a removable singularity.
 
Yeah... MATLAB seems to say the same thing.
 

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