Even Wave Function in 1D Symmetric Potentials: Can We?

hokhani
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I like to know in one dimensional symmetric potentials, can we have any even wave functions which be zero in the origin?
 
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Do you want to construct an even potential V(x) such that ψ(x=0) = 0?

In an attractive potential having bound states there are two reasons for ψ(x) = 0; one is the generalization of standing waves like sin(kx) or cos(kx); of course you will never get an even wave function for such a standing wave b/c its Taylor expansion would start with the x1 term.

The second possibility is that the potential forces the wave function to zero; but b/c in QM you can have nonzero ψ even in classically forbidden regions (think about a double-well potential constructed like V(x) ~ (x+a)(x-a)) the only way to force the wave function ψ(x) to zero is a divergent potential V(x) → ∞.

So one simple possibility would be a combination of to infinite square wells with V=0 for x in [-b,-a] and x in [+a,+b], and V=∞ outside these two wells.
 
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Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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