Evolution of uniformly accelerated system

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Consider system with Hamiltonian H. If this system is attached to inertial observer its
evolution is described by unitary operator: U_t = \exp(t H) where t is time
measured by inertial observer. What if the observer accelerates (with constant
acceleration in its comoving frame). Is it stil true that U_\tau = \exp(\tau H)
wher \tau is time measured by accelerating observer (the length of its
world line). Is hamiltonian idependent of type of observer whom we attache the system to?
 
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No, the unitary operator is not necessarily U_\tau = \exp(\tau H). The Hamiltonian of the system will depend on the type of observer it is attached to. In general, the Hamiltonian of a system in a curved spacetime is given by the Hamilton-Jacobi equation, which depends on the metric of the spacetime. For an accelerating observer, the spacetime metric is different than for an inertial observer, so the Hamiltonian will be different.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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