- #1
Bogus_Roads
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Homework Statement
Multiply the given equation by the given integrating factor and solve the exact equation.
Homework Equations
ydx+(2x-yey)dy=0, [tex]\mu[/tex](x,y)=y.
The Attempt at a Solution
M=y2, N=2xy-y2ey
Integrating N=[tex]\Psi[/tex]y WRT x I get
xy2-((1/3)y3ey + y2ey)+h(x)=[tex]\Psi[/tex](x,y)
Differentiating [tex]\Psi[/tex](x,y) WRT x, I get
[tex]\Psi[/tex]x=y2+h'(x)
Thus h'(x)=0, and
[tex]\Psi[/tex](x,y)=xy2-((1/3)y3ey + y2ey)
The correct answer is xy2-(y2-2y+2)ey=c...
What am I doing wrong? When I solve for psi in the opposite way I get the same wrong answer from before...
Thanks in advance!