Exact Solutions to General Relativity & Einstein's Field Eqns.

shounakbhatta
Messages
287
Reaction score
1
Hello,

Can anybody tell me what is meant by exact solution to General Relativity or exact solution to Einstein's field equation.

-- Shounak
 
Physics news on Phys.org
It means explicit solution i.e. the components of the metric can be written down explicitly in terms of well known functions in some coordinates.
 
The rumored exact solutions...
 
Thanks for the reply. But in general is it that the metric cannot be written down in co-ordinates? Is it a special case?
 
shounakbhatta said:
Thanks for the reply. But in general is it that the metric cannot be written down in co-ordinates? Is it a special case?

There are local coordinates and the metric will have its components in terms of the coordinates, but in general the functions involved will not be the ones that have names say polynomials, exponentials...
 
shounakbhatta said:
Thanks for the reply. But in general is it that the metric cannot be written down in co-ordinates? Is it a special case?

No, it is always possible to to write the metric down "in coordinates". But doing this requires solving the Einstein Field Equation for the specified conditions... And sometimes those equations are so hairy that no one has found a solution and we're forced to use numeric methods instead.

Note that I said "specified conditions", not "specified coordinates". If you can solve the EFE for a given situation using one coordinate system, a coordinate transformation will get you the same solution expressed in another coordinate system.
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Back
Top