Examination of a two-pulse rectifier

[polibuda]

Homework Statement

I'm testing a two-pulse rectifier. I am considering a system with an inductive load. I don't understand why the current I1 is slightly greater than the current I2, and when we add the diode D0, the current I2 is slightly greater than the current I1. Does it have to do with charging and discharging the coil? I don't understand why, with a resistive load, the current I1 is much greater than the current I2, and adding the D0 diode doesn't change the parameter values. I put the results in the tables. Could somebody me help with these problems?

Relevant Equations

lack

 

[Baluncore]

Lu and Lv are effectively in series with the input current. That will extend the conduction time of the T rectifiers at the end of that phase.

The voltage drop across T1+T4 or T2+T3 is higher than the voltage drop across Do. Since negative Lo voltage is less with Do in circuit, the Lo current will fall slower during the rectifier switching crossover; V_L = L * di/dt ;

RMS or peak currents ?
I think you must plot the currents and switch voltages against time to understand the effect of Do.