Exception to second derivative test? (Or am I doing something wrong?)

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SUMMARY

The discussion centers on the application of the second derivative test to the function y=(x^2-1)^4. The stationary points identified are (-1,0), (0,1), and (1,0). While the second derivative test indicates a local maximum at x=0, it fails for x=1 and x=-1, which are actually local minima. This discrepancy arises because the second derivative at these points equals zero, indicating potential inflection points, but further analysis reveals they are not inflection points due to the even order of the lowest non-zero derivative.

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Dramacon
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Homework Statement


I'd always used the 2nd derivative test for the nature of stationary points. But I came across this equation in one of my exercises, for which the test doesn't seem to work at all.

Find the stationary points of: y=(x^2-1)4, stating the nature of each.

Homework Equations


Using normal calc: the stationary points are at (-1,0), (0,1) and (1,0)

The Attempt at a Solution


Although the double derivative works for when x=0, (local max)

When I sub in the values x=1 or x=-1, the value I end up with is 0: suggesting that these points are stationary points of inflection, when they are not (they're actually local minima).

Please help. :)
 
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Hi Dramacon! :smile:

From http://en.wikipedia.org/wiki/Inflection_point#A_necessary_but_not_sufficient_condition :wink:

A necessary but not sufficient condition

If x is an inflection point for f then the second derivative, f″(x), is equal to zero if it exists, but this condition does not provide a sufficient definition of a point of inflection. One also needs the lowest-order (above the second) non-zero derivative to be of odd order (third, fifth, etc.). If the lowest-order non-zero derivative is of even order, the point is not a point of inflection. (An example of such a function is y = x4).​
 
Ah, I see! Thank you! :)
 

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