Existence of a Constant c in Subset X with Complement Measure 0

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Homework Statement
Suppose X is a subset of R such that its complement has Lebesgue measure 0. Show that there exists a c such that for all integers n, c + n is in X.

The attempt at a solution
I've been thinking about this for a while and I just don't see how such a c could exists. Any tips?
 
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As an example of such a subset X, take the irrational numbers.
 
I thought about that already. I know that X must contain some irrational c, but how do I know it will contain c + n for all integers n?
 
Think about the intersection of all of the sets (X-i) for i an integer. Could it possibly be empty?
 
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I had thought of the interesection of the sets X + n for all integers n but that thought didn't develop further. But now that you wrote X - i, I now see how it works. Thanks.
 
Hmm...maybe I wrote to soon. If the intersection is empty, then the intersection of X - 1, X - 2, etc. is a subset of the complement of X and so has measure 0. But where is the contradiction?
 
If the intesection is empty, then the complement of the intersection is R. Write down an expression for the complement of the intersection expressed as a union of complements. Do you see a contradiction now?
 
Oh, I see it now. Duh! Thanks.
 
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