Expand a function in terms of Legendre polynomials

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To expand a function defined on the interval (a,b) in terms of Legendre polynomials, the transformation u = (2x-a-b)/(b-a) is used to map the function onto the interval (-1,1). The discussion highlights confusion around the term "maps the function," clarifying that it means the transformation allows the function to be expressed in a new interval. The key point is to demonstrate that the function composition f∘u is a valid restriction from (a,b) to (-1,1). Understanding this mapping is essential for applying Legendre polynomial expansion. Overall, the transformation is crucial for facilitating the expansion process.
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Problem:
Suppose we wish to expand a function defined on the interval (a,b) in terms of Legendre polynomials. Show that the transformation u = (2x-a-b)/(b-a) maps the function onto the interval (-1,1).

How do I even start working with this? I haven't got a clue...
 
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I do not speak english in everyday life, and so the words "maps the function onto the interval (-1,1)" seems confusing to me. I would normally interpret them as "u is such that u\circ f:(a,b)-->(-1,1)". But that does not seem to make sense, since we do not know the form of f. What does make sense, is to understand it as "u is such that f\circ u:(a,b)-->R is the same as f:(-1,1)-->R". In other words, you need to show that f\circ u is a restriction of f. But that is easy, you only need to show that u is onto from (a,b) to (-1,1).
 
Ok, I'm really not good at linear algebra so I think I'll jump this problem. ;)
 
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