Expanding Logarithms with Radicals

AI Thread Summary
The discussion revolves around expanding the logarithm of a radical, specifically log2√x. Participants explore the correct way to express √x using fractional exponents, leading to the realization that log2√x can be rewritten as (1/2)log2x. There is confusion regarding whether this expression simplifies further, but the key takeaway is the application of the logarithmic property log(a^b) = b·log(a). Additionally, there is a challenge posed about the misconception that log2(√x) equals 1/2 for all x. Understanding these concepts is crucial for accurately expanding logarithmic expressions with radicals.
Deagonx
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Homework Statement


log2√x

Homework Equations


The Attempt at a Solution



I thought that it might be something like log2x - log2x but that's not right. The book examples don't have any radicals.
 
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Deagonx said:

Homework Statement


log2√x


Homework Equations





The Attempt at a Solution



I thought that it might be something like log2x - log2x but that's not right. The book examples don't have any radicals.
Write √x with a fractional exponent.
 
That makes a lot more sense... So is it 1/2(log2x) or (log2x)/2(log2x)
 
Deagonx said:
That makes a lot more sense... So is it 1/2(log2x) or (log2x)/2(log2x)

##log(a^b) = b \cdot log(a)##
 
Deagonx said:
That makes a lot more sense... So is it 1/2(log2x) or (log2x)/2(log2x)
Why would you even consider that log_2(\sqrt{x})= 1/2 for all x?
 
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