jadelamlam said:
That's right.
2.through the narrow tube to the surrounding environment
Yes.

But remember, the drop of water is in there too. So what must happen to the drop of water if the air already in the tube is to escape?
3.i dun know
Do you mean that,the pressure inside and outside the tube are equal,so the air particles from both sides can't "push" the drop of water towards?
Almost, yes. That is at least the approximate idea.
If my assumption is correct,I still have a question.
Replace the drop of water by a cork that fits the shape of the narrow tube.
It won't fall although there is gravity exerts on it.
It is because there is friction between the surface of boiling tube and cork.
friction = gravity,so the cork won't drop into the tube.
No, I'd say ignore friction for this problem. The friction on the water is not important for this problem. Also ignore friction for the cork analogy. There is something else more significant.
This is related to force exerts on an object instead of the air pressure,when should we use "pressure" and "force" to explain such phenomenon?
(sorry my physics is really poor,I hope sb can understand what I mean)
Yes! it is about pressure! You've got it.
If you squeeze a gas within a container into a smaller volume, what happens to the gas' pressure?
Force is equal to the pressure multiplied by the area upon which the pressure acts. The
net force may involve different pressures and different corresponding areas.
There is atmospheric pressure above the water droplet. And the pressure of the gas below the water droplet (in the tube structure) is
almost identical to atmospheric pressure. But it's not
exactly identical (assuming the force of gravity on the water droplet is acting in the direction down the tube).
Can you determine how the
difference in pressure above and below the water droplet cancels out the force of gravity on the water droplet? (This is a subjective, rhetorical question.)