Expectation of a Joint Continuous rv

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SUMMARY

The discussion focuses on calculating the expectation E(XY) for a joint continuous random variable defined by the joint probability density function f(x,y) = 6(x-y) within the limits 0 < y < x < 1. The formula for expectation is clarified as E(g(X,Y)) = ∫ g(x,y)f(x,y) dy dx, where g(X,Y) is specified as XY. The integration limits are explicitly stated, guiding the calculation of the expected value.

PREREQUISITES
  • Understanding of joint probability density functions
  • Familiarity with double integrals in calculus
  • Knowledge of expectation in probability theory
  • Basic concepts of random variables and their distributions
NEXT STEPS
  • Study the properties of joint continuous random variables
  • Learn about calculating expectations using double integrals
  • Explore the concept of marginal distributions and their calculations
  • Investigate applications of joint distributions in statistical modeling
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Students and professionals in statistics, data science, and applied mathematics who are working with joint distributions and expectations in probability theory.

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fx,y = 6(x-y)dydx, if 0<y<x<1

how do you find E(XY),
i know the formula...g(x,y)fxy(x,y)dydx

but i don't know what 'g(x,y)' represents and the limits to use??
 
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The expectation of g(X,Y) is \mathbb{E}(g(X,Y)):= \int g(x,y)f(x,y)\mathrm{d}x\mathrm{d}y

with the integral being taken over the whole of the probability space of X and Y.

So here, g(X,Y) is XY, and the limits are given to you: 0<y<x<1.
 

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