Expected value of bivariate pdf

Click For Summary

Discussion Overview

The discussion revolves around the expected value of a bivariate probability density function (pdf), specifically focusing on the calculations for E[X] and E[Y]. Participants explore the integration process required to compute these expected values and provide examples to illustrate their points.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Brendan questions whether the expected value E[X] or E[Y] of a bivariate pdf is calculated using single or double integrals, providing an example with f(x,y) = x + y.
  • Another participant suggests that a double integral is necessary to compute the expected value, indicating that single integration yields only the conditional expectation of one variable with respect to the other.
  • A participant proposes specific limits for integration (0 < x < 1, 0 < y < 1) and calculates E[X] as 7/12, asking for confirmation of this result.
  • A later reply reiterates the calculation of E[X] as 7/12, without providing further clarification or confirmation of its correctness.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct method for calculating the expected values, and there are differing interpretations of the integration process required for bivariate pdfs.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the integration limits and the specific form of the bivariate pdf used in the examples.

boneill3
Messages
126
Reaction score
0
Is the expected value E[x]or E[y] of a bivariate pdf fXY(xy)

\int x f(x,y)dx

or

E[y]

\int y f(x,y)dy ?

example if f(x,y) = x+y

E[X] = \int x *(x+y)dx


regards
Brendan
 
Physics news on Phys.org
You need to carry out the double integral. A single integration gives the conditional expection of one variable with rexpect to the other.
 
So just say you had the lmits of 0<x<1 0<y<1
The expected value would be:
[itex] E[X] = \int_{0}^{1}\int_{0}^{1} x *(x+y)dxdy<br /> <br /> = 7/12<br /> [\latex]<br /> Is that right?[/itex]
 
Sorry,

[itex] E[X] = \int_{0}^{1}\int_{0}^{1} x *(x+y)dxdy<br /> <br /> = 7/12[/itex]

regards
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
444
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
5K