Expected values of random variables

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The discussion centers on the definition and understanding of expected values of random variables, particularly focusing on the random variable X1 and its mean, denoted as μ. Participants clarify that μ represents the expected value, while \overline{X} is the average of observed values. An example involving coin flips illustrates the distinction between the expected value of a single flip (0.5) and the actual average from a series of flips (0.4). The conversation emphasizes the importance of differentiating between theoretical expectations and empirical results. Understanding these concepts is crucial for grasping the fundamentals of probability and statistics.
sid9221
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I don't completely understand why the area of the proof circled in red is true.

Any advice would be appreciated.

https://dl.dropboxusercontent.com/u/33103477/Q1.jpg
 
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X1 is a random variable whose mean is \mu by definition. Can you elaborate on your confusion?
 
Office_Shredder said:
X1 is a random variable whose mean is \mu by definition. Can you elaborate on your confusion?

Where is this defined ? Is is part of the definition of 'Expectation' ?
 
Why don't you tell us what you think X1 is, and what \mu is, and we can work from there.
 
Office_Shredder said:
Why don't you tell us what you think X1 is, and what \mu is, and we can work from there.

μ=\frac{\sum X_i}{N}

x_1 is just a variable
 
sid9221 said:
μ=\frac{\sum X_i}{N}

No, the thing on the right hand side is \overline{X}, not \mu. To give an example, suppose I flip ten coins, and assign a value of 1 to a heads, and 0 to a tails. I might get the following:

1,0,0,1,0,0,1,0,1,0.

\mu in this context is the expected value of a single flip of the coin, which is .5. \overline{X} is the average of the flips I actually made, which is .4. X1 is the value of the first flip, which in this case happens to be 1, but hopefully it's clear that E(X1) = .5 before I actually flip the coin since X1 is just an arbitrary flip of the coin.
 
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