Explain the difference of hyodrogen ions

AI Thread Summary
The pH of a solution is calculated using the formula pH = -log[H], where [H] represents the concentration of hydrogen ions. A neutral solution like water has a pH of 7, indicating a hydrogen ion concentration of 10^-7 M. Acidic solutions, such as those with a pH of 3, have a higher concentration of hydrogen ions at 10^-3 M. Conversely, strong bases with a pH of 11 have a lower concentration of hydrogen ions at 10^-11 M. Understanding these differences is crucial for grasping the concept of acidity and basicity in solutions.
chemical
Messages
14
Reaction score
0
The pH of a solution is determined by the value of -log[H] where [H] is the molar concentration of hydrogen ions in the solution

The pH of water is 7, the pH of an acid is 3 and the pH of a strong base solution is 11. Explain the difference of hyodrogen ions in each of these solutions


i have no idea how to get started on this one... 7 = -log7 once again no idea... i know that the answer will be to the negative power like 1/100 but can't get started. help would be appreciated :smile:
 
Last edited:
Physics news on Phys.org
pH = -\log_{10}([H])

They give you the values for the left hand side, so plug those in, and solve for the corresponding [H] values. [H] is going to be your unknown here.

cookiemonster
 
Originally posted by cookiemonster
pH = -\log_{10}([H])

They give you the values for the left hand side, so plug those in, and solve for the corresponding [H] values. [H] is going to be your unknown here.

cookiemonster

cheers
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top