Explaining the Solution for secx=4 in Calculator Format (Ti-89) for Range 0-2pi

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To solve sec(x) = 4 using a TI-89 calculator for the range 0 to 2π, the solution can be expressed as 2π(weird notation)1 ± arccos(1/4) in radians. The "weird notation" indicates that there are multiple solutions due to the periodic nature of the cosine function. The TI-89 provides this notation to signal that the function crosses the x-axis at multiple points. Understanding the graph of cos(x) helps in recognizing that solutions occur at intervals, not just at the principal value. This highlights the importance of interpreting calculator outputs correctly when dealing with trigonometric equations.
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Homework Statement



I was supposed to use my calculator to get the answer of secx=4 for the range 0 to 2pi. I use the Ti-89.

Homework Equations



calculator format solve (secx=4,x)

The Attempt at a Solution



I get an answer, but it has a weird notation at the end of 2pi.

2pi(weird notation)1 +/- arccos (1/4) In radians, obviously

The notation looks like a lower case e, but instead, it breaks about halfway under the top loop. Sorry, for my vague info. I can't take a picture of it because i don't half no camera
 
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The TI-89 has the weird symbol to let you know their are more than 1 solution. Take f(x)=cos(x) for example. If you input it into the 89 for where f(x) = 0 you should right away know that f(x) will cross 0 in more than 1 place. The 89 will give you something like (pi/2)(weird symbol). But you know right away from the graph (if you know what it looks like) that it does not only cross at pi/2 but at every half wavelength starting at pi/2 (if your talking of only the positive side).
 
Jonathan G said:
The TI-89 has the weird symbol to let you know their are more than 1 solution. Take f(x)=cos(x) for example. If you input it into the 89 for where f(x) = 0 you should right away know that f(x) will cross 0 in more than 1 place. The 89 will give you something like (pi/2)(weird symbol). But you know right away from the graph (if you know what it looks like) that it does not only cross at pi/2 but at every half wavelength starting at pi/2 (if your talking of only the positive side).
Alright, thank you.
 
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