Exploding Object Problem: Solving for the Speed of the Third Fragment

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The discussion centers on solving the Exploding Object Problem involving a 48.0-kg body that breaks into three fragments after an explosion. The first fragment (9.5 kg) moves at 385 m/s in the positive y direction, while the second fragment (3.0 kg) moves at 413 m/s in the negative x direction. The conservation of momentum principle is applied to find the speed of the third fragment, with calculations indicating an error in the initial approach. The correct application of momentum conservation in both x and y directions is emphasized, leading to the conclusion that the third piece's velocity must balance the momentum of the other two fragments. The thread concludes with the realization of an error in calculations, suggesting a potential resolution to the problem.
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Homework Statement


A 48.0-kg body is moving in the direction of the positive x-axis with a speed of 389 m/s when, owing to an internal explosion, it breaks into three pieces. One part, whose mass is 9.5 kg, moves away from the point of explosion with a speed of 385 m/s along the positive y axis. A second fragment, whose mass is 3.0 kg, moves away from the point of explosion with a speed of 413 m/s along the negative x axis. What is the speed of the third fragment? Ignore effects due to gravity.

M= 48kg
M1 = 9.5kg
M2= 3 kg
M3= 35.5 kg
Fnet = 0


Homework Equations


p=mv
m1v1+m2v2+m3v3=mv0


The Attempt at a Solution




been trying to do p = 48*389 = 18672
then 3*-413 +35.5 * Vx = 18672
then get vx of 560.87
then do vy = 9.5*385 + 35.5 vy = -103.02
then vx^2+ vy^2 = v3^2 and i get 551.33 and its not accepting
 
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shadowice said:

Homework Statement


A 48.0-kg body is moving in the direction of the positive x-axis with a speed of 389 m/s when, owing to an internal explosion, it breaks into three pieces. One part, whose mass is 9.5 kg, moves away from the point of explosion with a speed of 385 m/s along the positive y axis. A second fragment, whose mass is 3.0 kg, moves away from the point of explosion with a speed of 413 m/s along the negative x axis. What is the speed of the third fragment? Ignore effects due to gravity.

M= 48kg
M1 = 9.5kg
M2= 3 kg
M3= 35.5 kg
Fnet = 0


Homework Equations


p=mv
m1v1+m2v2+m3v3=mv0


The Attempt at a Solution




been trying to do p = 48*389 = 18672
then 3*-413 +35.5 * Vx = 18672
then get vx of 560.87
then do vy = 9.5*385 + 35.5 vy = -103.02
then vx^2+ vy^2 = v3^2 and i get 551.33 and its not accepting

Remember the following:

(1) Momentum before = Momentum After

(2) Momentum is a vector quantity so the momentum in the x direction must be conserved and separately momentum in the y direction must be conserved.

(3) Consequently the third piece moves in such a way as to guarantee number (2)
 
figured out my error can delete this topic or close whichever you do
 
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