What Makes the Hilbert Cube Cubelike?

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The Hilbert cube is considered "cubelike" primarily because it is homeomorphic to I^inf, which reflects its infinite-dimensional structure. It is defined as a subset of l^2 space where each coordinate is constrained between 0 and 1/n, creating a product topology that resembles a cube when limited to three dimensions. Different definitions exist, such as using the product [0,1] x [0,1/2] x [0,1/3] x ... for ease of manipulation, but all closed intervals are homeomorphic to [0,1]. This flexibility in definition highlights the Hilbert cube's properties in relation to Hilbert spaces. Ultimately, its cubelike nature stems from its geometric and topological characteristics in infinite dimensions.
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So, what exactly is "cubelike" about the hilbert cube?

I think I am having trouble "visualizing" it. Is it just called that because it it homeomorphic to I^inf. ?
 
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I realize there are different ways of defining the hilbert cube, so this question probably doesn't make much sense.

My class defined it to be the subset of l^2 space given by 0<x_n<1/n (actually less than or equal to).
 
the hilbert cube is the product [0,1]^{\mathbb{N}} with the product topology. if you take the product of just 3 of them it looks like a cube, hence the name. some people like to define it as [0,1] x [0,1/2] x [0,1/3] x ... x [0, 1/n] x ... just because it's easier to work with, but it doesn't really matter since all closed intervals are homeomorphic to [0,1]
 
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actually a cube is a product of any closed intervals. someone working in a hilbert space would rather use [0,1] x [0,1/2] x [0,1/3] x ... x [0, 1/n] x ... as the definition since it is isometric, rather than just homeomorphic, to a subspace of itself.
 
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