At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by A = 10(0.82)t. (a) What was the intial amount taken? 10 mg (b) What percent of the drug leaves the body each hour? 18% (c) How much of the drug is left in the body 6 hours after the dose is administered? A = 10(0.82)6 A = 3.04 mg (d) How long is it until only 1 mg of the drug remains in the body? 1 = 10(0.82)t 1/10 = 0.82t ln (1/10) = t ln0.82 t = ln (1/10) / ln0.82 t = 11.6028 hours Are these correct?