Exponentially damped dipole - line broadening

unscientific
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For an EM wave close to the transition frequency ##\omega_{21}##, we assume the dipole moment to be exponentially damped and oscillating:

p(t) = p(0) e^{-\frac{\gamma}{2}t} cos(\omega_0 t)

Why do we expect the electric field to be proportional to ##\dot p##?

Taken from my lecturer notes on laser and atomic physics:

laser1.png
 
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If a dipole moment changes(it is created by charge accelerations), it emit EM wave in classic treatment. Therefore we can get E(t) proportional to dp/dt.
 
abbas_majidi said:
If a dipole moment changes(it is created by charge accelerations), it emit EM wave in classic treatment. Therefore we can get E(t) proportional to dp/dt.
Please explain the "classical treatment".
 
unscientific said:
Please explain the "classical treatment".
In classical physics accelerated charges can emit EM waves, it is used in making antenna. A dipole changes with time is a antenna and its behavior is explained by classical physics compleatly. Therefore if you use ' electric field to be proportional to ##\dot p##', you consider atoms like antenna or in other words you use classical treatment of atoms.
 
Hi. I have got question as in title. How can idea of instantaneous dipole moment for atoms like, for example hydrogen be consistent with idea of orbitals? At my level of knowledge London dispersion forces are derived taking into account Bohr model of atom. But we know today that this model is not correct. If it would be correct I understand that at each time electron is at some point at radius at some angle and there is dipole moment at this time from nucleus to electron at orbit. But how...
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