Expressing an Arbitrary Vector in Terms of Noncoplanar Vectors

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SUMMARY

An arbitrary vector V can be expressed in terms of three noncoplanar vectors A, B, and C using the formula: V = [V,B,C]A/[A,B,C] + [V,C,A]B/[A,B,C] + [V,A,B]C/[A,B,C]. The discussion highlights the importance of the scalar triple product, with [V,B,C] representing V's projection onto the plane formed by B and C. The hint provided in the homework statement is crucial for deriving the coefficients a, b, and c in the expression V = aA + bB + cC.

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  • Understanding of vector projections
  • Familiarity with scalar triple products
  • Knowledge of noncoplanar vectors
  • Basic vector algebra
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  • Study the properties of scalar triple products in vector calculus
  • Learn how to compute vector projections onto noncoplanar vectors
  • Explore applications of vector decomposition in physics
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Homework Statement


Show that an arbitrary vector V can be expressed in terms of any three noncoplanar vectors, A, B, C, according to:

V = [V,B,C]A/[A,B,C] + [V,C,A]B/[A,B,C] + [V,A,B]C/[A,B,C]


Homework Equations


A Hint is given:
We know that V can be expressed as aA + bB +cC; to find a, take the scalar product of V with BxC


The Attempt at a Solution


I tried to solve this one by relating the projections of V to 3 arbitrary vectors, A, B, C, but I couldn't get to the answer above. I'm also not sure how the hint will help me either. Could someone please help me get started on this because I am all out of ideas.

thanks
 
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I'm assuming [V,B,C] is the triple product V.(BxC), right? Then what is [V,B,C]? It's (aA+bB+cC).(BxC). BxC is perpendicular to B and C, so those parts of the dot product are zero. This leaves you with [V,B,C]=aA.(BxC)=a*[A,B,C]. Put that into your formula and treat the other two terms the same way.
 
Wow, so the hint gave it away -- i can't believe i didn't see that. Thanks a lot for the help though!
 

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