Expressing an Integral as a sum of terms

In summary: In fact, the Riemann sum is used to approximate the integral, but it only becomes equal to the integral when the number of partitions approaches infinity. So, in summary, the left side is a Riemann sum used to approximate the integral on the right side, but they are not equal unless the number of partitions approaches infinity. Therefore, we cannot write it as an equal sign.
  • #1
Apashanka
429
15
Homework Statement
Suppose a given function f(x) and continuous x limit is given from say a to b.
Now if it is asked to say that sum over the values of f(x) over x between a and b.
Relevant Equations
e.g
Can we write it as
$$f(a)+f(a+dx)+f(2a+dx)+f(3a+dx)+.......f(b)=\int^b_a f(x)dx$$
e.g
Can we write it as
$$f(a)+f(a+dx)+f(2a+dx)+f(3a+dx)+...f(b)=\int^b_a f(x)dx$$...(?)
Although $$\int f(x)dx$$ given the area tracked by thr function with the x-axis between a and b
Thanks.
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
Apashanka said:
Homework Statement:: Suppose a given function f(x) and continuous x limit is given from say a to b.
Now if it is asked to say that sum over the values of f(x) over x between a and b.
Homework Equations:: e.g
Can we write it as
$$f(a)+f(a+dx)+f(2a+dx)+f(3a+dx)+...f(b)=\int^b_a f(x)dx$$

e.g
Can we write it as
$$f(a)+f(a+dx)+f(2a+dx)+f(3a+dx)+...f(b)=\int^b_a f(x)dx$$...(?)
Although $$\int f(x)dx$$ given the area tracked by thr function with the x-axis between a and b
Thanks.

I might be missing something here, but don't we need to multiply each of the [itex] f(x_i) [/itex] by a [itex] \delta x [/itex] to get an area? Otherwise, I thought that the area under a certain f(x) value for a continuous function is 0.

As to the rewritten version, what if [itex] b < 2a [/itex]. To me it would seem more intuitive to write out something like:
[tex] Integral = f(a)\delta x + f(a + \Delta x)\delta x + f(a + 2\Delta x)\delta x + f(a + 3\Delta x)\delta x + ... + f(b)\delta x [/tex]
 
  • #3
Apashanka said:
Can we write it as
$$f(a)+f(a+dx)+f(2a+dx)+f(3a+dx)+...f(b)=\int^b_a f(x)dx$$
No.
As already mentioned by another poster, your coefficients are in the wrong places. The sum above is often written as
##f(a)+f(a + \Delta x)+f(a + 2\Delta )+f(a + 3\Delta ) + \dots + f(a + n \Delta x)##
where ##\Delta x = \frac {b - a} n##
This sum is called a Riemann sum, which is used to approximate a definite integral. For suitable functions (i.e., functions that are continuous on the interval [a, b]), the integral ##\int_a^b f(x) dx## is defined to be equal to the limit of the Riemann sum, as n goes to infinity.
 
  • #4
Apashanka said:
$$f(a)+f(a+dx)+f(2a+dx)+f(3a+dx)+...f(b)=\int^b_a f(x)dx$$...(?)

The two sides will not be equal. As the user above said, the left side is a Riemann Sum and only used as approximation.
 
  • #5
currently said:
As the user above said, the left side is a Riemann Sum
... that has no relationship with the integral on the right side.
 

1. What is the purpose of expressing an integral as a sum of terms?

Expressing an integral as a sum of terms allows us to break down a complex integral into smaller, more manageable parts. This can make it easier to evaluate the integral and understand the function it represents.

2. How do you express an integral as a sum of terms?

To express an integral as a sum of terms, we use a method called partial fraction decomposition. This involves breaking down the integrand into simpler fractions and then integrating each term individually.

3. Can any integral be expressed as a sum of terms?

Not all integrals can be expressed as a sum of terms. This method is most commonly used for rational functions, where the numerator and denominator are polynomials. It may also work for some other types of functions, but it is not a universal method.

4. Are there any benefits to expressing an integral as a sum of terms?

There are several benefits to expressing an integral as a sum of terms. It can make the integral easier to evaluate, especially if the terms are simpler to integrate than the original function. It can also help us understand the function better by breaking it down into smaller parts.

5. Are there any drawbacks to expressing an integral as a sum of terms?

One potential drawback of expressing an integral as a sum of terms is that it can be a time-consuming and tedious process, especially for more complex functions. Additionally, not all integrals can be expressed in this form, so it may not always be a viable method.

Similar threads

  • Calculus and Beyond Homework Help
Replies
2
Views
137
  • Calculus and Beyond Homework Help
Replies
9
Views
536
  • Calculus and Beyond Homework Help
Replies
4
Views
641
  • Calculus and Beyond Homework Help
Replies
2
Views
830
  • Calculus and Beyond Homework Help
Replies
9
Views
749
  • Calculus and Beyond Homework Help
Replies
7
Views
1K
  • Calculus and Beyond Homework Help
Replies
2
Views
452
  • Calculus and Beyond Homework Help
Replies
14
Views
2K
  • Calculus and Beyond Homework Help
Replies
4
Views
838
  • Calculus and Beyond Homework Help
Replies
15
Views
1K
Back
Top