Factorising x^3 + 216 to Include (x + 6)

[Alkatran]

I need to factorise x^3 + 216 to include (x+6):

(x + 6) \ (x^3 + 216) (lim where x approaches -6)

I broke it down to (x + 6i)(x^2 - 36i) ... but that's no good.

 

[arildno]

Well, shouldn't polynomial division work fine?

 

[Pyrrhus]

Remember

X^3 + Y^3 = (X+Y)(X^2-XY+Y^2)

 

[Pyrrhus]

He has

\frac{x+6}{x^3 + 216}

\frac{x+6}{x^3 + 6^3}

 

[Alkatran]

I got it fine before I even came back. I was trying to remember how to do long division and the cube rule that you guys posted. The start of the year, still getting restarted...