gerald V said:
- It is kind of dumb to speak about "seeing" something in the context of a fall into a BH
Not dumb, just limited. If you're outside the horizon, you will never see (as in, receive light from) anything that happens at or inside the horizon. But you can still see things that happen outside the horizon, including infalling objects that haven't yet crossed the horizon.
zio
gerald V said:
- If an object falls into a BH, this occurs within finite proper time of any observer hoovering or orbiting outside the horizon
That isn't what I said; I said that the infalling object reaches the horizon in a finite proper time according to
its own clock. (Actually, I only implied it; but it's correct.)
Whether or not the object reaches the horizon in a finite time according to an observer outside the horizon, is a question that does not have a unique, well-defined answer; it depends on how you choose your coordinates. There is no absolute meaning to the "time", according to a given observer, at which events that are spatially separated from that observer take place.
gerald V said:
- Despite of the lack of a visual signal, the observer can verify that the infall actually took place by estimating the spacetime geometry as those of a black hole more massive (and possibly with different angular momentum and charge) as the original one
In most cases, he doesn't even have to estimate the geometry, because the mass, charge, and angular momentum of the infalling object are so small, compared to those of the hole, that they can be ignored. So the observer can just use the geometry of the original hole, and compute that the object will fall in in a finite proper time by its own clock.
gerald V said:
I have thought that for those case the usual Schwarzschild coordinates are physical in the sense that the time coordinate is identic with the proper time of an observer hoovering at those position.
No, it isn't. The Schwarzschild time coordinate only matches the proper time of an observer who is at rest at infinity. And it is only well-defined at all outside the horizon.
gerald V said:
Does the outside observer lose information as a consequence of the infall?
We don't know for sure. See below.
gerald V said:
the gravitational waves produced by the infall
The waves observed by LIGO were produced by two black holes merging, not by an ordinary object falling into a black hole. The latter process will not produce any observable GWs.
gerald V said:
Together with the new parameters of the hole, doesn't this allow to completely reconstruct the object fallen in (in principle)?
Classically, you don't even need the new parameters of the hole or any GWs. Classical physics is deterministic; the infalling object's initial conditions already tell you everything about what is going to happen to it in the future, so no new information is added when it falls into the hole.
The whole "information loss" problem is a
quantum problem, not a classical one; it arises because we believe that classical GR breaks down close to the singularity inside the black hole, and some sort of quantum gravity effect takes over. Quantum mechanics, as we understand it, does not allow for information loss (this property is called "unitarity"); but we do not have a satisfactory picture of how the quantum information contained in the infalling object is preserved when it reaches the area at the center of the hole that, classically, is where the singularity is. Hawking radiation, firewalls, etc. are all part of our attempts to construct such a satisfactory picture, which, as I've said, are still not complete.