Falling Objects Problem for Calculus

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SUMMARY

The discussion centers on solving the Falling Objects Problem using the free-fall equation s=490t^2, where s represents distance in centimeters and t represents time in seconds. Participants calculated the time taken for two balls to fall 160 cm, arriving at the solution by manipulating the equation to find t. The average velocity was clarified to be determined using the formula distance = rate * time, rather than requiring the derivative of the function. This approach simplifies the process of finding average velocity over a specified distance.

PREREQUISITES
  • Understanding of kinematic equations, specifically the free-fall equation s=490t^2
  • Basic calculus concepts, including derivatives and their applications
  • Knowledge of average velocity calculation methods
  • Familiarity with algebraic manipulation of equations
NEXT STEPS
  • Study the derivation and application of the free-fall equation s=490t^2
  • Learn how to calculate average velocity using distance and time
  • Explore the concept of derivatives in the context of motion equations
  • Investigate other kinematic equations for different types of motion
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Students studying calculus, physics enthusiasts, and educators looking to enhance their understanding of motion under gravity and average velocity calculations.

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Homework Statement


The multiflash photograph in Figure A shows two balls falling from rest. The vertical rulers are marked in centimeters. Use the equation s=490t^2 (the free-fall equation for s in centimeters and t in seconds) to answer the following questions:
a) How long did it take the balls to fall the first 160 cm? What was their average velocity for the period?


Homework Equations





The Attempt at a Solution


160cm=490t^2
square root of (160/490)
My question is how do you find the average velocity? Do you take the derivative of the first equation which would be 490t and plug 160 cm in again?
 
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Firstly, the derivative of s(t) = 490t^{2} will not be 490t.

Secondly, if you want to find the average of a linear function over an interval, wouldn't it be best to know the endpoints of the function on that interval? Remember that velocity is a function of time, not distance.

EDIT: Actually, I take that back. You really don't even need to find the derivative. You can just use the equation distance = rate * time, seeing as you just solved for time.
 
Last edited:

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