Falling Particle: Solving for Initial Velocity and Acceleration

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    Falling Particle
AI Thread Summary
The discussion focuses on solving for the initial velocity (v0) and acceleration (a) of a particle thrown upwards, which passes a distance "d" twice—once while ascending and once while descending. The correct formulas derived for these calculations are v0 = d * [(t1 + t2) / (t1 * t2)] and a = (2 * d) / (t1 * t2). The problem emphasizes starting with the position equation for an object under constant acceleration. Participants express difficulty in arriving at the correct solution, highlighting the need for a clear understanding of the motion equations. The discussion ultimately clarifies the relationship between time, distance, and velocity in projectile motion.
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Homework Statement



Particle was thrown directly upwards. Point which is in distance “d” from the beginning of movement is passed by the particle two times. Once going upwards in time “t1” and second time going downwards in time “t2” from the beginning of the movement. What was the initial speed(v0) and the acceleration(a) of the particle?

Homework Equations



I really do not know how to start with this example.

The Attempt at a Solution



I have tried every possible solution that I was capable of, but I’m not able to come up with the correct answer which should be

v0=d*[(t1+t2)/(t1*t2)]

and

a=(2*d)/(t1*t2)
 
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Start with the equation for position o an object under constant acceleration.

Point which is in distance “d” from the beginning of movement is passed by the particle two times.

This defines the coordinate system for you: initial velocity is v0 and initial height is 0.
 
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