Faraday's Law and EMF calculation

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SUMMARY

The forum discussion centers on the calculation of Electromotive Force (EMF) using Faraday's Law. The user calculates the EMF based on a NdFeB Magnet with a strength of 1.33 Tesla, a coil with 6 windings, and a surface area of 0.0002 m². The formula applied is EMF = -N * (change in magnetic flux), leading to a calculated EMF of -0.00399 volts per rotation. The user seeks confirmation on the accuracy of this calculation.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Basic knowledge of electromotive force (EMF) calculations
  • Familiarity with magnetic flux and its units (Tesla, m²)
  • Experience with coil windings and their impact on EMF
NEXT STEPS
  • Research the application of Faraday's Law in practical electromagnetic systems
  • Learn about the effects of coil winding configurations on EMF output
  • Explore the properties of NdFeB magnets and their applications in electromagnetism
  • Investigate the impact of varying rotation speeds on EMF calculations
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Students and professionals in electrical engineering, physicists studying electromagnetism, and hobbyists working on electromagnetic projects will benefit from this discussion.

barendfaber
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Hi,

I found this site with a calculation for EMF: http://www.6pie.com/faradayslaw.php. I just want to see if I have this right.

Magnet Surface: Height (0.05 m) * Width (0.004 m) = Area 0.0002 m2.
Coil windings: 6
Rotations per second: 5
NdFeB Magnet in N42 (1.33 Tesla) (I will reduce this as not all the coil windings will not be right next to the magnet surface)

EMF / V = -N * change in (( tesla * area meters squared)/ seconds)
= -6 * ((0.665 * 0.0002)/.2)
= -6 * 0.000665
= -0.00399

Is the above assumption of possible EMF per rotation correct?
 
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