Ferrous Sulfate Crystallization

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To obtain pure ferrous sulfate heptahydrate (FeSO4·7H2O) from a liquor rich in Fe2+, Fe3+ sulfate, and sulfuric acid, the main challenge is the highly acidic pH of -0.2, which complicates the crystallization process. The current method yields a mixture of FeSO4·7H2O and Rhomboclase (H5O2)+Fe+++(SO4)2•2(H2O) with impurities. Reducing iron (III) to iron (II) has proven ineffective. To achieve pure FeSO4·7H2O, it may be necessary to adjust the pH to a more neutral level, potentially using a controlled addition of a base to precipitate impurities while promoting the crystallization of FeSO4·7H2O. Exploring alternative crystallization techniques or solvents that can stabilize Fe2+ ions under acidic conditions could also be beneficial.
Thermo
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I am trying to obtain ferrous sulfate heptahydrate crystal from a liquor which is rich in Fe2+ and Fe3+ sulfate and sulfuric acid. However I can only achieve crystal (more likely powder) form of FeSO4.7H2O (37%) mixed with 58% Rhomboclase (H5O2)+Fe+++(SO4)2•2(H2O) with minor impurities. How can I achieve pure FeSO4.7H2O under these conditions? The liquor is too acidic and the pH is -0,2. I tried to reduce iron (III) ions to iron (II) with reducing agents but that didn't work well.
 
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