Feynman's Path integral formulation

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Feynman's path integral formulation does not violate relativity, as the paths generated are mathematical constructs rather than physical trajectories. While some paths may suggest speeds faster than the speed of light (c), the probability amplitude for such occurrences remains zero. This ensures that no actual particles can exceed the speed of light, maintaining consistency with relativistic principles. The discussion highlights the distinction between mathematical tools and physical reality in quantum mechanics. Overall, the formulation is a valid approach that does not conflict with established relativistic laws.
cragar
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Does Feynman's path integral formulation violate relativity ,
we get path's that are faster than c.
 
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Feynman paths are just a mathematical tool, they are not a problem, they can do whatever they want. The problem would arise if the probability amplitude for a particle to travel faster than c would come non-zero... And this is not happening.

Why didn't you post it in Quantum Physics? Would have received more attention...
 

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