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Let f(x), g(x) be in F[x]. Show that if g(x)|f(x) and f(x)|g(x), then f(x)=kg(x) for some k in F.

Since g(x)|f(x), then f(x)=g(x)r(x) for some r(x) in F[x].

Similarily, since f(x)|g(x), then g(x)=f(x)s(x)

So f(x)=f(x)s(x)r(x)

Since g(x)|f(x), then f(x)=g(x)r(x) for some r(x) in F[x].

Similarily, since f(x)|g(x), then g(x)=f(x)s(x)

So f(x)=f(x)s(x)r(x)

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