Hello,
Thank you for sharing your project with me. It seems like you are trying to eliminate the residual ripple in your load by adding a 1 F "saving capacitor." This is a common solution to reduce ripple in electronic circuits, as capacitors are able to store and release energy quickly. However, there are a few things to consider before implementing this solution.
Firstly, it is important to ensure that the "saving capacitor" is rated for the appropriate voltage and has a low enough ESR (equivalent series resistance) to effectively filter out the ripple. If the capacitor is not rated for the voltage in your circuit, it could potentially fail and cause further issues. Additionally, if the ESR is too high, the capacitor may not be able to effectively filter out the ripple.
Secondly, it is important to consider the overall capacitance in your circuit. Adding a 1 F capacitor in parallel with your 4700 µF capacitor will increase the total capacitance of your circuit. This may affect the charging and discharging times of your circuit, potentially causing unintended consequences.
Lastly, it is important to consider the cost and space constraints of adding an additional capacitor to your circuit. Depending on the size and cost of the "saving capacitor," it may not be a practical or cost-effective solution.
In summary, adding a "saving capacitor" in parallel with your existing capacitor may be a viable solution to reduce the residual ripple in your circuit. However, it is important to carefully consider the specifications, overall capacitance, and practicality of this solution before implementing it. I hope this helps and wish you success in your project.
Best,