Final Charge on Lower Plate of Water-Dipped Capacitor

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In a discussion about a parallel plate capacitor with one plate dipped in water, the initial charge on the lower plate is Q, while the upper plate has a charge of 2Q. The dielectric constant of water is denoted as K, and the question revolves around determining the final charge on the lower plate after dipping it in water. One participant claims the final charge is 3Q/2 and seeks validation of this answer. However, others emphasize the importance of showing work for accurate feedback, suggesting that help is contingent upon demonstrating the reasoning behind the solution. The conversation highlights the challenges of seeking assistance without providing detailed calculations.
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Homework Statement


A parallel plate capacitor with the separation between the plates as 'd' has its lower plate dipped in water. Before dipping, the lower plate has charge Q, while the upper plate has charge 2Q. Let K be the dielectric constant of water. What will be the final charge on the lower surface of the plate dipped in water.


Homework Equations



The Attempt at a Solution


I am not showing the equations and attempt to my solution.
The answer I got is 3Q/2, can anyone comment on if my answer is correct.
 
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If you post your work I'll tell you whether or not it is correct.
 
Mindscrape said:
If you post your work I'll tell you whether or not it is correct.

its so much time taking to show the work... if u can just tell yes or no.. its sufficient for me.. thanks in advance..
 
Mindscrape is trying to help you. You may want to re-read this https://www.physicsforums.com/showthread.php?t=94379 towards the top of this subforum page. It will explain that help is only given to those who show their work.
 
i m just forced to post my questions in this homework forum because of the warnings i get.. these questions are not homewrk questions.. i m just trying to understand the subject myself.
 

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