Final Equil. of 0.03 kg Ice & 0.18 kg Water @ 25°C

Thread starter elin0523
Start date Apr 5, 2011
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Equilibrium Thermal Thermal equilibrium

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In the scenario, 0.03 kg of ice and 0.18 kg of water are initially at 0°C, and steam at 100°C is introduced until all the ice melts. The final temperature of the mixture is recorded at 25°C. To determine the final amount of water in the container, the heat gained by the ice melting and the subsequent heating of the resulting water must equal the heat lost by the steam. The calculations will involve the specific heat of water and the latent heat of fusion for ice, ensuring no heat loss occurs. The final equilibrium will consist of the total mass of water from the melted ice and the initial water, totaling 0.21 kg.

Apr 5, 2011

elin0523

0.03 kg of ice and 0.18kg of water are initially in equilibrium at 0 degree celcius in a container. Steam at 100 degree celcius is then passed by in until all the ice melted. The final temperature of the mixture as measured is 25 degree celcius. How much water is in the container in the final equilibrium ? Assume no heat loss or heat gain through other means.

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Apr 5, 2011

ehild

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Show please what you have tried.

ehild

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