Final velocity with air resistance

AI Thread Summary
The discussion revolves around a physics problem involving an object shot vertically with air resistance. The user successfully solved the first part of the problem, calculating the maximum height reached, but struggles with determining the speed upon hitting the ground. Responses emphasize the need to adjust the analysis for the second part, noting that air resistance remains proportional to velocity squared and does not change sign during descent. The user expresses frustration over not receiving a complete solution and considers deleting the thread. Ultimately, the conversation highlights the importance of self-effort in problem-solving.
enanthate
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Ok so I am working on this problem and can only get through the first question, the second question keeps stumping me.

I have uploaded the question along with my calculations for part a so you can see what I'm doing.


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A object of mass (m) is shot vertically up with V0 200 m/s.
Air resistance R is proportional with the square root of the velocity, R= -mkv^2
where k= 0.010m-1

a) How high does the object reach.

This one I have solved:

h= (1/2k) * ln [(g+kv^2)/g]


b)

What is the speed the object has when it hits the ground?

------

I just can't get the right answer to b, I keep getting the same velovity as V0 which can't be right.

IF it is possible to hand write your work or write it mathematically I would really appreciate it.


My work in attachment as both .pdf or .jpg, whatever you prefer.

In advance, thank you very much!
 

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You looked like you understood what was going on in solving the first part. Why did you give up on the second part?

Remember, the second part is slightly different from the first. From solving the first part, you know how far the object must fall, and you know its initial velocity. Can't you adjust your analysis from the first part to reflect this?

And no, no one is going to write it out neatly for you; you must do the work yourself.
 
Think a bit about the term -kmv2. It doesn't change sign when your object starts to descend.
 
Do you mean the air resistance is proportional to the velocity squared. I think that is what you have written as an equation.
 
SteamKing said:
You looked like you understood what was going on in solving the first part. Why did you give up on the second part?

Remember, the second part is slightly different from the first. From solving the first part, you know how far the object must fall, and you know its initial velocity. Can't you adjust your analysis from the first part to reflect this?

And no, no one is going to write it out neatly for you; you must do the work yourself.

Ok. I did not realize that no one will show me the solution here or I wouldn't have bothered posting. No point then is there.

Thanks for the input everyone, I can't find a delete button maybe a mod can delete the thread for me?
 
I'm sorry you feel that way. We can't help you if you are not willing to help yourself and put forth some effort.
 
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