Final volume of a gas using the ideal gas equations

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SUMMARY

The discussion centers on calculating the final volume of a gas using the combined gas equation, specifically addressing the lack of necessary information such as mass or volume for the second gas. Participants agree that without these values, it is impossible to derive the final volume accurately. Temperature conversions from Fahrenheit to Kelvin are also highlighted as needing correction. The conversation emphasizes the importance of having complete data to solve gas-related problems effectively.

PREREQUISITES
  • Understanding of the combined gas law
  • Familiarity with temperature conversion (Fahrenheit to Kelvin)
  • Knowledge of pressure units (psig and InHg)
  • Basic principles of gas behavior and equations
NEXT STEPS
  • Study the combined gas law and its applications
  • Learn about pressure unit conversions, specifically between psig and InHg
  • Explore the ideal gas law and its implications for gas calculations
  • Review temperature conversion methods and their importance in gas equations
USEFUL FOR

Students in chemistry or physics, educators teaching gas laws, and professionals in fields requiring gas calculations will benefit from this discussion.

Krokodrile
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Homework Statement
An oxygen cylinder contains 1 ft^3 gas at `70 F and 200 Psig. What will the volume of the gas be if it passes into a receptacle of dry gas at 90 F and 0.3 inHg above atmospheric pressure? The barometer indicates 14.7 In/lb^2
Relevant Equations
P1V1/T1 = P2V2/T2
Hey there! for this problem i try to use the combinate gas ecuation. First of all the values its necesary to have it in absolutes:
70 F = 527.67 K
90 F = 549.67 K
The ecuation looks like: (200 psig) (1 ft^3)/529.67 K = (0.3 InHg) V2/549.67 K I can eliminate "K" but not psig with InHg for obtain the ft^3 of V2.

And i don't know for what its the value of the barometer.
 
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Is this the exact wording of the problem?
 
Chestermiller said:
Is this the exact wording of the problem?
yes, it is. The word-word statement. Meanwhile i try to resolved, i noticed that if don't have a mase or a volume value in the second gas i can't obtain all the values of that gas. But, yes, its the exact wording of the problem say be the teacher. So, i guees that its possible to resolve
 
Krokodrile said:
yes, it is. The word-word statement. Meanwhile i try to resolved, i noticed that if don't have a mase or a volume value in the second gas i can't obtain all the values of that gas. But, yes, its the exact wording of the problem say be the teacher. So, i guees that its possible to resolve
Well, in my judgment, there is not enough information provided to answer this question.
 
Chestermiller said:
Well, in my judgment, there is not enough information provided to answer this question.
Yes. i agree. Maybe if the second gas had mass i wold to use V = mRT/P, but this is not the case. I don't find any formule of the gases for resolve the problem. Maybe the teacher forget the mass or he volume value. This is my opinion, but, i would like know your opinion about why its not enogh information and have a more idea for comment it in the class.
 
Also, your temperature conversions need correcting.
 

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