FINANCIAL MATH: Question on Compounding Interest Semi-annually

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To determine how long it takes for $100 to grow to $500 at a 6.5% interest rate compounded semi-annually, the formula A = P(1 + i)^(n*t) is used. The values are set as A = $500, P = $100, and i = 3.25% (half of 6.5%). The equation simplifies to 5 = 1.0325^(2n). To solve for the exponent 2n, natural logarithms can be applied, leading to ln(5) = 2n * ln(1.0325), allowing for the calculation of n. This method effectively provides the time required for the investment to reach the desired amount.
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HELP! i know this is an easy question to solve but i need some help. THANKS for any help in advance!

QUESTION: Determine, to the nearest half year, how long it will take $100 to amount to $500 at 6 1/2% compounded semi-annually.

Using the formula A=P(1 + i)*to the power of*n
where A is the final amount, P is the present value, i is the interest rate and n is the number of compounding periods i have gotten to:
A=$500 P=$100 i=6.5%/2 (because it's semi-annually)=3.25% n=2 x n (because it's semi-annually)
In the FORMULA"
A = P(1+i)*to the power of*n
500 = 100(1+0.0325)*to the power of*2n
5 = 1.0325*to the power of*2n
*I am sure the answer is right to this point, I'm just not sure of how to solve for the exponent 2n. thank you for any help!
 
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Hello Nicole,

In financial mathematics, the best method in solving for unknown time is by the use logarithms, preferably, the natural logarithm \ln.

So far, you're solution is right.

From 5 = 1.0325^{2n}, apply the natural log to both sides

<br /> \ln 5 = \ln 1.0325^{2n}<br />


By a property of logarithims,

<br /> \ln 5 = 2n \cdot \ln 1.0325<br />

I think you can handle it from here :)
 
A(t) = P(1 + \frac{r}{n})^{(n)(t)}
 
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