Find a, b, c for f(x) with x-intercepts at (0,0) & (8,0) and slope 16 at x=2

  • Thread starter Thread starter Optical24
  • Start date Start date
Click For Summary
SUMMARY

The problem requires finding coefficients a, b, and c for the quadratic function f(x) = ax^2 + bx + c, given specific conditions: x-intercepts at (0,0) and (8,0), and a slope of 16 at x=2. The x-intercepts indicate that c=0 and the roots of the equation are x=0 and x=8. By applying the derivative f'(x) = 2ax + b and substituting x=2 to set the slope to 16, the values of a and b can be determined. The solution yields a = 2 and b = -16, resulting in the function f(x) = 2x^2 - 16x.

PREREQUISITES
  • Understanding of quadratic functions and their properties
  • Knowledge of derivatives and slope calculations
  • Familiarity with solving systems of equations
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of quadratic functions in detail
  • Learn about derivatives and their applications in finding slopes
  • Explore methods for solving systems of equations
  • Practice problems involving quadratic equations and their graphs
USEFUL FOR

Students studying algebra, mathematics educators, and anyone interested in mastering quadratic functions and their applications in calculus.

Optical24
Messages
1
Reaction score
0
I'm struggling with this problem:

Find numbers a, b, and c so that the graph of f(x) = ax^2 + bx + c has x-intercepts at (0,0) and (8,0), and a tangent with slope 16 where x=2

Can anyone help?
 
Physics news on Phys.org
Probably, but not until you show us that you've made an attempt at this problem.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 15 ·
Replies
15
Views
2K