Find a transition matrix from bases?

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To find the transition matrix Pab from basis a = {1, x, x^2} to basis b = {-2 - 2x + 3x^2, 1 + 2x - x^2, -1 - x + 2x^2}, one must express each vector in basis a as a linear combination of the vectors in basis b. This involves solving a system of equations for each vector in basis a, determining the coefficients that represent their coordinates in basis b. For example, to find the coordinates of x^2 in basis b, set up the equation x^2 = u_1 b_1 + u_2 b_2 + u_3 b_3 and solve for u_1, u_2, and u_3. Repeat this process for the other basis vectors to construct the full transition matrix. The transition matrix can then be compiled from the resulting coordinate vectors.
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Homework Statement


I have 2 bases, a = {1, x, x^2} and b = {-2 - 2x + 3x^2 , 1 + 2x - x^2 , -1 - x + 2x^2} of P2.

Find the transition matrix Pab.

How is this done??


Homework Equations


Since this is Linear Algebra, there aren't really any relevant "Equations" as such. More logic based. Right?



The Attempt at a Solution


I am quite muddled. Best I could get was to make [v]s = [1; 1; 1] (Thats a vertical matrix of 1s)

Not quite sure where to go from here.
 
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The transition matrix is computed with coordinates. For example, the coordinates of the vector 'x^2' in the ordered basis 'a' are (0, 0, 1). Now, write this in the coordinates in the basis 'b.' This can be done by solving a system of equations: x^2 = u_1 b_1 + u_2 b_2 + u_3 b_3 where u_i is an unknown coefficient (to be solved) and b_1, b_2, b_3 are elements in the ordered basis 'b.' Once solved for u_1, u_2, and u_3, the coordinates of x^2 in the ordered basis 'b' are (u_1, u_2, u_3). This gives the first column of the transition matrix. Do a similar thing for the remaining elements in the ordered basis 'a.'
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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