Find all solutions of sin on the interval

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Homework Help Overview

The problem involves solving the equation 7sin(2x) - 13sin(x) = 0 for all solutions in the interval 0 ≤ x < 2π. The original poster attempts to apply the double angle formula for sine to transform the equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the double angle formula and the resulting equation. There is a focus on factoring and identifying common terms in the equation, with some questioning the structure of the equation itself.

Discussion Status

Some participants have provided guidance on identifying common factors in the equation. There is an indication that progress has been made, as one participant mentions finding the solutions, although the details of the solutions are not fully explored in the discussion.

Contextual Notes

Participants are working under the constraint of finding all solutions within a specified interval, which may influence their approach to the problem. There is also a mention of confusion regarding the terms involved in the equation.

nickb145
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Homework Statement



i have

solve 7sin(2x)-13sin(x)=0
for all solutions 0≤X<2p
I used the double angle formula for sin(2x)=2sin(x)cos(x)


The Attempt at a Solution



I'm getting stuck near the end
7(2sin(x)cos(x)-13sin(x))
14sin(x)cos(x)-13sin(x)

now I am stuck
 
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nickb145 said:

Homework Statement



i have

solve 7sin(2x)-13sin(x)=0
for all solutions 0≤X<2p
I used the double angle formula for sin(2x)=2sin(x)cos(x)


The Attempt at a Solution



I'm getting stuck near the end
7(2sin(x)cos(x)-13sin(x))
14sin(x)cos(x)-13sin(x)

now I am stuck

What you wrote aren't equations. An equation must have two sides separated by an '='. In this case, your right hand side (RHS) equals 0.

In that final equation, can you find a common factor between the two terms?
 
Curious3141 said:
What you wrote aren't equations. An equation must have two sides separated by an '='. In this case, your right hand side (RHS) equals 0.

In that final equation, can you find a common factor between the two terms?

That is what i am trying ot figure out. I would just say sin(x) could be factored out.

the 14sin and the 13sin are just throwing me off.
 
Last edited:
Yep that was it. found the solutions. it was sin(x) that was the common factor. sin(x)=0 and cos(x)=13/14

x= pi, 0 .3801 and 5.902
 

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