Find asymptotes for rational functions

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SUMMARY

The discussion centers on finding asymptotes for the rational function f(x) = (x^2 - 1) / (x - 1). The user initially simplifies the function to f(x) = x + 1 for x ≠ 1, leading to the conclusion that there is a horizontal asymptote at y = x + 1. However, the correct conclusion is that there are no asymptotes for this function since it simplifies to a linear function, which does not have asymptotes. The misunderstanding arises from the misinterpretation of the function's behavior at the point of discontinuity.

PREREQUISITES
  • Understanding of rational functions and their properties
  • Knowledge of limits and asymptotic behavior
  • Familiarity with polynomial long division
  • Basic graphing skills for rational functions
NEXT STEPS
  • Study the concept of discontinuities in rational functions
  • Learn about polynomial long division for simplifying rational expressions
  • Research the definitions and types of asymptotes in calculus
  • Practice finding asymptotes for various rational functions
USEFUL FOR

Students studying calculus, particularly those focusing on rational functions and asymptotic analysis, as well as educators seeking to clarify concepts related to limits and asymptotes.

ssampak
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Homework Statement



Find asymptotes for f(x) = (x^2 -1) / (x - 1). (if exist)

Homework Equations



g(x) is a (horizontal or oblique) asymptote if lim |f(x) - g(x)| = 0
(here, lim is to be limit as x goes to infinity. don't know how to type it)

or

if q(x)/p(x) = g(x) + r(x)/p(x) where dimension of r(x) is smaller than that of p(x)

The Attempt at a Solution



f(x) = (x^2 - 1) / (x-1) = x+1 (where x ≠ 1)

then lim |f(x) - (x+1)| = 0 so asymptote is x+1.

But the answer is 'no asymptote'. What am I missing?
 
Physics news on Phys.org
If f(x) = (x^2 - 1) / (x-1) = x+1, the doesn't that just mean that f(x)=x+1 ? and that is what kind of graph?
 

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