Find Centroid of U: First Octant Ellipsoid

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SUMMARY

The centroid of the solid region U in the first octant bounded by the ellipsoid defined by the equation (x^2)/4 + (y^2)/9 + (z^2)/4 = 1 is calculated using elliptic coordinates. The correct centroid coordinates are determined to be (3/8, 9/16, 3/8) after applying the Jacobian transformation for the volume element. The volume of the ellipsoid is confirmed to be 2π, but it is emphasized that the concept of mass does not apply to geometric figures like ellipsoids.

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Homework Statement


Let U be the solid region in the first octant bounded by the ellipsoid (x^2)/4 + (y^2)/9 + (z^2)/4 = 1. Find the centroid of U.

Homework Equations


The Attempt at a Solution



I tried to do this problem but I'm not sure if my answer is right. First, I find the mass and I got 2pi. Then I find the moment, and divided it by mass, and I got the centroid to be like (1,9/8,1). But I'm not sure if I did it right or not. Can anyone help me?
 
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That can't be right. Since the "y-length" is 3, and the other lengths 2, the y coordinate of the centroid must be 3/2 the other coordinates.

I did this by changing to "elliptic coordinates". More precisely, I let
[itex]x= 2\rho cos(\theta) sin(\phi)[/itex], [itex]y= 3\rho sin(\theta) sin(\phi)[/itex] and [itex]z= 2\rho cos(\phi)[/itex]- spherical coordinates 'altered' to fit the ellipse.
Calculating the Jacobian gives [itex]12\rho^2 sin(\phi)d\rho d\phi d\theta[/itex] as the differential. The ellipse in the first octant take [itex]\rho[/itex] from 0 to 1, [itex]\phi[/itex] from 0 to [itex]\pi/2[/itex] and [itex]\theta[/itex] from 0 to [itex]\pi/2[/itex].
I get (3/8, 9/16, 3/8) as the centroid.

(By the way, [itex]2\pi[/itex] is the volume of the ellipse, not the "mass". "Centroid" is a purely geometrical concept and geometric figures do not have "mass".)
 

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