- #1

shandsy

- 5

- 0

## Homework Statement

(there's a diagram that shows a crate on a plane inclined 19.29° above the horizontal)

Find the coefficient of kinetic friction.

θ = 19.29°

m

_{crate}= .205 kg

## Homework Equations

F

_{f}= F

_{N}*μ

_{k}

F

_{g}= mg

F

_{N}= cosθ*mg

## The Attempt at a Solution

I drew out a free-body diagram for the crate as it slid down the incline including the x and y components of F

_{g}. I came up with the following:

F

_{g}= 2.009 N

F

_{gy}= cos(19.29°)*2.009N = 1.896 N

F

_{gx}= sin(19.29°)*2.009N = 0.664 N

F

_{N}= F

_{gy = 1.896 N Ff = Fgx = 0.664 N However, if I plug these values back in, I get .350 as the value for μk, but I know that the correct answer is supposed to be .93. Am I right in assuming that Fgx = Ff? I feel like I'm completely missing something...}