(there's a diagram that shows a crate on a plane inclined 19.29° above the horizontal)
Find the coefficient of kinetic friction.
θ = 19.29°
mcrate = .205 kg
Ff = FN*μk
Fg = mg
FN = cosθ*mg
The Attempt at a Solution
I drew out a free-body diagram for the crate as it slid down the incline including the x and y components of Fg. I came up with the following:
Fg = 2.009 N
Fgy = cos(19.29°)*2.009N = 1.896 N
Fgx = sin(19.29°)*2.009N = 0.664 N
FN = Fgy = 1.896 N
Ff = Fgx = 0.664 N
However, if I plug these values back in, I get .350 as the value for μk, but I know that the correct answer is supposed to be .93.
Am I right in assuming that Fgx = Ff? I feel like I'm completely missing something...