(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

(there's a diagram that shows a crate on a plane inclined 19.29° above the horizontal)

Find the coefficient of kinetic friction.

θ = 19.29°

m_{crate}= .205 kg

2. Relevant equations

F_{f}= F_{N}*μ_{k}

F_{g}= mg

F_{N}= cosθ*mg

3. The attempt at a solution

I drew out a free-body diagram for the crate as it slid down the incline including the x and y components of F_{g}. I came up with the following:

F_{g}= 2.009 N

F_{gy}= cos(19.29°)*2.009N = 1.896 N

F_{gx}= sin(19.29°)*2.009N = 0.664 N

F_{N}= F_{gy = 1.896 N Ff = Fgx = 0.664 N However, if I plug these values back in, I get .350 as the value for μk, but I know that the correct answer is supposed to be .93. Am I right in assuming that Fgx = Ff? I feel like I'm completely missing something...}

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# Homework Help: Find coefficient of kinetic friction on an inclined plane.

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