Find components of vectors on F

AI Thread Summary
To find the u and v components of a vector, the same principles used for the x and y components apply. The process involves visualizing a right triangle where the hypotenuse represents the force magnitude (F), and the adjacent side corresponds to the u component. The angle between the force vector and the u component is crucial for calculations, specifically using the cosine function. For the u component, the formula is cos Θ = u/F, where Θ is the angle (21 degrees in this case). Similarly, the v component can be determined using the same trigonometric approach.
bbarke00
Messages
6
Reaction score
0
1. Problem is pictured here. http://engineeringhomework.net/statics/hw1p14.html" I have already found the x and y components, but I don't know how to get the u and v as shown.
 
Last edited by a moderator:
Physics news on Phys.org
You would find them in exactly the same way you found x and y. To find the x component you can consider the right triangle between the force vector, the the x component and the y component. You know that the cos of the angle equals the adjacent component (the x comp in this case) divided by the hypotenuse (the magnitude of the force), and in this way you can solve for the x comp

cos Θ = A/H = x/F

Well, for the u and v, you do the same thing. You consider a right triangle, where the hypotenuse is F, the adjacent side is the u component, and the other side is a component perpendicular to u (not v). Θ is the angle between the force vector and u, in this case 21, and you can solve for u

cos Θ = A/H = u/F

Solving for v is a similar problem
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top