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Find difference in pressure in this water intake pump

  • Thread starter mb85
  • Start date
  • #1
44
0
A water intake at a pump storage reservoir (Fig. 14-44) has a cross-sectional area of 0.87 m2. The water flows in at a speed of 0.35 m/s. At the generator building, at distance D = 180 m below the intake point, the cross-sectional area is smaller than at the intake and the water flows out at 9.8 m/s. What is the difference in pressure, in megapascals, between inlet and outlet?

Im using Burnoulli's Equation:

P1 -P2 = density(g)(Y1- Y2) + 1/2 (density)(V2^2 - V1^2)
density of water = 1000
so = (1000)(9.8)(180) + 1/2(1000)(9.8^2 - 0.35^2)
= 1811958.75Pa/1.01x10^5Pa
= 17.94 atm

But then answer is in MPa, So then i get 1.794 x10^-6 MPa

But that is not correct, is the analysis i made incorrect? I think i am missing something key in the problem. Thanks in advance.
 

Answers and Replies

  • #2
FredGarvin
Science Advisor
5,066
7
Without looking at your problem set up your conversion from atm to MPa is incorrect. 17.9 atm = 1.81 MPa.
 
  • #3
537
0
Why did you convert from Pa to atm? Just convert Pa to MPa.
 
  • #4
44
0
to be honest, im not sure i did. silly.

but is the analysis i did correct for the problem?
 
  • #5
12
0


Did he do the question correct?
 

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