Find dy/dx by implicit differetiation HELP IMMEDIATLY

[Mindscrape]

You are really struggling with the product rule, but look at it as substitution.

u = cosx and v = siny

d/dx u v = uv' + vu'

so

d/dx cosx*siny = cosx*d/dx(siny) + siny*d/dx(cosx)

Try showing what the derivative of d/dx(x*cosx) is.

 

[afcwestwarrior]

isnt the derivative of cos sin and sin cos

 

[afcwestwarrior]

so does it look like this cos x/ cosy + siny /sin x

the bottoms are derivatives

 

[Mindscrape]

In words, this means take the derivative of sine with respect to y (where the implicit differentiation comes in) and multiply it by cosine, then add the derivative of cosine multiplied by sine.

You keep throwing out equations without having any mathematical reason for getting there, which will definitely not get you to the answer. Now, I understand you are desperate, but you got to stop flailing and just think about it. I have given you everything you need, the rest is up to you.

 

[HallsofIvy]

Okay, do you KNOW what the product rule and chain rule are?

Do you know what the derivative of sin(x)cos(x) is?

Do you know how to find the derivative of y if x+ y= 1 and y is a function of x?

In other words, let's find out what you do know before we start making suggestions!

(Oh, and the answer to

isnt the derivative of cos sin and sin cos

is "NO!")

I strongly recommend that you go back and review your basic differentiation laws.