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Find electric field on a point due to a charged arc.

  • Thread starter cgar666
  • Start date
  • #1
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Homework Statement


A charge of 25nC is uniformly distributed along a circular arc (radius = 2.0 m) that is subtended by a 90-degree angle. What is the magnitude of the electric field at the center of the circle along which the arc lies?

I'm not getting the right answer however, so if someone would be able to help me solve this question and point out what I'm doing wrong I"d be very appreciative.

Homework Equations


E = k*Q/r^2
θ=s/r
dq = λ ds


The Attempt at a Solution


2j0f5za.jpg
 

Answers and Replies

  • #2
1,540
134
The limits of integration should be [itex]\frac{-\pi}{4}[/itex] to [itex]\frac{\pi}{4}[/itex].

The arc length is [itex]\frac{(2)(\pi)(r)}{4}[/itex].
 
  • #3
56
2
The limits of integration should be [itex]\frac{-\pi}{4}[/itex] to [itex]\frac{\pi}{4}[/itex].
No, cgar666 limits of integration are perfectly fine. They may just lead to more math. You can use symmetry to slightly clean up some algebra as well.
 

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