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Find eqn of cylinder of height

  1. Apr 24, 2012 #1

    sharks

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    Gold Member

    1. The problem statement, all variables and given/known data
    How to find the equation of cylinder: [itex]x^2+y^2=4[/itex] from z=0 to z=2?

    2. Relevant equations
    [tex](x-a)^2+(y-b)^2=r^2[/tex]

    3. The attempt at a solution
    I can't figure out how to implement the z-coordinate into the general equation of cylinder. In the latter, the height is taken as infinite in both opposite directions (upward and downward).
     
  2. jcsd
  3. Apr 24, 2012 #2

    Mark44

    Staff: Mentor

    Doesn't this work?
    [itex]x^2+y^2=4; 0 \leq z \leq 2[/itex]
     
  4. Apr 24, 2012 #3

    sharks

    User Avatar
    Gold Member

    Hi Mark44! :smile:

    Actually, that's how the equations are originally given in the problem but i was wondering if there is a way to combine those 2 into a single equation, since the height of the cylinder is known.

    In my mind, maybe something like that: [itex]x^2+y^2 + (z-c)^n=4[/itex] even though it's now become closer to a sphere!
     
    Last edited: Apr 24, 2012
  5. Apr 24, 2012 #4

    Mark44

    Staff: Mentor

    No, there's no way to combine the equation and inequality into one.
     
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