Find Equivalent Inductance for 3 Inductors: 6mH, 8mH, 6mH

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The circuit consists of two 6.0 mH inductors in series, which combine to 12.0 mH, and this is in parallel with an 8.0 mH inductor. The equivalent inductance is calculated using the formula for parallel inductors, resulting in a total inductance of 4.8 mH. After one 6.0 mH inductor fails, the repair person needs to replace all three inductors with a single equivalent inductor. The correct inductance to use for the replacement is 4.8 mH. The rules for combining inductances in series and parallel follow the same principles as resistances.
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A circuit contains two inductors of 6.0 mH inductance in series placed in parallel with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repair person wants to replace all three inductors with one inductor of equivalent inductance. What inductance should she use?



1. 3.0 mH

2. 4.8 mH

3. 3.4 mH

4. 11 mH

5. 20 mH

Two 6 mH in series = L1+L2 = 6+6= 12mH
this is in parallel with 8mH

so,,total L = 12*8/20 = 4.8mH

Is this correct?
 
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yes, it is correct. The rules for series and parallel inductances are the same as
those for resistances.
 
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