Find force (N) of atmosphere on area

AI Thread Summary
To calculate the force exerted on the eardrum due to sound pressure, the formula used is F = PA, where pressure (P) is the net pressure difference. The eardrum area is approximately 53 mm², which converts to 53 x 10^-6 m². The pressure difference at the threshold of pain is ±200 Pa, leading to a net pressure of 200 Pa. Therefore, the correct force calculation should be F = 200 Pa x 53 x 10^-6 m², resulting in a force of approximately 0.0106 N. This indicates that the initial calculation using atmospheric pressure was incorrect.
Calhoun295
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Homework Statement



Your eardrum has an area of about 53 mm2. Sounds become painful to your ear when the pressure variations that are involved in sound reach 200 Pa above and below normal air pressure. At this level, called the threshold of pain, how much force is exerted on your eardrum?

Homework Equations



Pressure=\frac{Force}{Area}

The Attempt at a Solution



F=PA
F= 101000N/m^2 (.053m^2)
F= 5353 N

I've tried normal atmosphere above and below 200Pa. The answer isn't correct according to wileyplus. I'm obviously doing it wrong, so what's wrong with my equation?
 
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Hi Calhoun295! :smile:

(try using the X2 tag just above the Reply box :wink:)
Calhoun295 said:
F=PA
F= 101000N/m^2 (.053m^2)
F= 5353 N

I've tried normal atmosphere above and below 200Pa.

No, you'll have Patm on one side of your eardrum, and Patm ± 200 on the other side … net pressure = ±200. :wink:
 
Also note that 53 mm^2= 53 \cdot ((10^{-3} m)^2) = 53\cdot 10^{-6} m^2
 
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