Find Force Needed to Lengthen Beam w/ Length, Y Modulus, Area

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Discussion Overview

The discussion revolves around determining the force required to lengthen a beam given its length, Young's modulus, and cross-sectional area. The focus is on the application of axial force and the relevant equations to calculate the required force for a specified elongation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about the existence of an equation to calculate the force needed to lengthen a beam based on its length, Young's modulus, and cross-sectional area.
  • Another participant provides the formula \(\delta = \frac{PL}{AE}\) as a relevant equation for this calculation.
  • A subsequent post presents a specific calculation using the provided values, resulting in a force of 728584640N, questioning whether this value seems excessively high.
  • Another participant suggests checking the units used in the calculations, specifically converting millimeters to meters.
  • The participant who performed the calculation asserts that they have already converted units, noting the conversion factors for millimeters and megapascals.

Areas of Agreement / Disagreement

There is no consensus on the correctness of the calculated force, as one participant questions the magnitude while another focuses on unit conversion. The discussion remains unresolved regarding the validity of the force calculation.

Contextual Notes

Participants have not explicitly stated all assumptions or the context of the beam's material properties, which may affect the calculations. The discussion does not clarify whether the values used are appropriate for the conditions described.

Ry122
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If I know only the length of the beam, the young's modulus, and the cross sectional area, is there an equation that I can use to determine what amount of force would be required to lengthen a beam by a specified amount? The force is being applied to the beam axially.
 
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[tex]\delta = \frac{PL}{AE}[/tex]
 
[tex] \P = \frac{deltaAE}{L}[/tex]

Using this with
delta=.4421207mm
E=200,000MPA
A=5776mm
L=701mm
The force is 728584640N
Doesn't this seem like too much?
 
Check your units. Convert all of the mm to m.
 
That's what I did. mm have prefix 10^-3
and Mega pascals has 10^6
 

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